數學分式題求間算1 x 5y 1 x 6y 1 x 8y 1 x 9y

時間 2022-09-25 01:45:02

1樓:數學新綠洲

1/(x-5y)-1/(x-6y)-1/(x-8y)+1/(x-9y)

=1/(x-5y)-1/(x-8y)+1/(x-9y)-1/(x-6y)

=[(x-8y)-(x-5y)]/[(x-5y)(x-8y)]+[(x-6y)-(x-9y)]/[(x-9y)(x-6y)]

=(-3y)/[(x-5y)(x-8y)]+ 3y/[(x-9y)(x-6y)]

=3y*

=3y*[(x-5y)(x-8y) - (x-9y)x-6y)]/[(x-9y)(x-6y)(x-5y)(x-8y)]

=3y*[(x²-13xy+40y²)-(x²-15xy+54y²)]/[(x-9y)(x-6y)(x-5y)(x-8y)]

=3y*(2xy-14y²)/[(x-9y)(x-6y)(x-5y)(x-8y)]

=6y²(x-7y)/[(x-9y)(x-6y)(x-5y)(x-8y)]

2樓:匿名使用者

1/x-5y-1/x+6y-1/x+8y+1/x-9y =(2/x-2/x)+(6y-5y+8y-9y) =0

3樓:周義

解:2x-6y/x^2-9y^2 =2(x-3y)/(x-3y)(x+3y)=2/(x+3y)2x+6y+1=0 2x+6y=-1x+3y=-1/2那麼2/(x+3y)=2÷(-1/2)=-4

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